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Determine Whether the Series Is Convergent or Divergent n=1(4n3n+1)n\sum _ { n = 1 } ^ { \infty } \left( \frac { 4 n } { 3 n + 1 } \right) ^ { n }

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Determine whether the series is convergent or divergent. n=1(4n3n+1)n\sum _ { n = 1 } ^ { \infty } \left( \frac { 4 n } { 3 n + 1 } \right) ^ { n }


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