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Find the Exact Area of the Surface Obtained by Rotating x=2cos3θ,y=2sin3θ,0θπ/2x = 2 \cos ^ { 3 } \theta , \quad y = 2 \sin ^ { 3 } \theta , \quad 0 \leq \theta \leq \pi / 2

question 61

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Find the exact area of the surface obtained by rotating the given curve about the x-axis. x=2cos3θ,y=2sin3θ,0θπ/2x = 2 \cos ^ { 3 } \theta , \quad y = 2 \sin ^ { 3 } \theta , \quad 0 \leq \theta \leq \pi / 2


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