Find the Integral Using an Appropriate Trigonometric Substitution $\int \frac{1}{x^{2} \sqrt{x^{2}+25}} d x$

question 8

Multiple Choice

Find the integral using an appropriate trigonometric substitution. $\int \frac{1}{x^{2} \sqrt{x^{2}+25}} d x$

• A) \(-\frac{\sqrt{x^{2}+25}}{5 x}+C\)
• B) \(\frac{\sqrt{x^{2}+25}}{5 x}+C\)
• C) \(\frac{\sqrt{x^{2}+25}}{25 x}+C\)
• D) \(-\frac{\sqrt{x^{2}+25}}{25 x}+C\)

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