The Linear Density of A $48$ M Long Rod Is $\frac{72}{\sqrt{x+1}} \mathrm{~kg} / \mathrm{m}$

question 44

Multiple Choice

The linear density of a $48$ m long rod is $\frac{72}{\sqrt{x+1}} \mathrm{~kg} / \mathrm{m}$ where x is measured in meters from one end of the rod. Find the average density of the rod.

• A) \(\rho_{\text {ave }}=21 \mathrm{~kg} / \mathrm{m}\)
• B) \(\rho_{\text {ave }}=11 \mathrm{~kg} / \mathrm{m}\)
• C) \(\rho_{\text {ave }}=41 \mathrm{~kg} / \mathrm{m}\)
• D) \(\rho_{\text {ave }}=26 \mathrm{~kg} / \mathrm{m}\)
• E) \(\rho_{\text {ave }}=23 \mathrm{~kg} / \mathrm{m}\)

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