The Mean Value Theorem for Integrals Says That If $f(t)$ Is Continuous on [

question 26

True/False

The Mean Value Theorem for Integrals says that if $f(t)$ is continuous on [ $a$ , $b$ ], then there exists a number m in [ $a$ , $b$ ] such that $f(m)=f_{a v e}=\frac{1}{a-b} \int_{a}^{b} f(t) d t .$

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