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Find an Equation of the Line Tangent to the Graph y=e9xx9+1y=\frac{e^{-9 x}}{x^{9}+1}

question 65

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Find an equation of the line tangent to the graph of y=e9xx9+1y=\frac{e^{-9 x}}{x^{9}+1} at the point where x = 0.


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