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Solve the Given Equation 4sin2θ4sinθ+1=04 \sin ^ { 2 } \theta - 4 \sin \theta + 1 = 0

question 113

Essay

Solve the given equation. 4sin2θ4sinθ+1=04 \sin ^ { 2 } \theta - 4 \sin \theta + 1 = 0


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