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Solve the Given Equation 2sin2θ7sinθ+3=02 \sin ^ { 2 } \theta - 7 \sin \theta + 3 = 0

question 26

Essay

Solve the given equation. 2sin2θ7sinθ+3=02 \sin ^ { 2 } \theta - 7 \sin \theta + 3 = 0


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