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Use Back-Substitution to Solve the Triangular System {x+2y+z=0y3z=14z=4\left\{ \begin{array} { r } x + 2 y + z = 0 \\y - 3 z = 1 \\4 z = - 4\end{array} \right.

question 14

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Use back-substitution to solve the triangular system. {x+2y+z=0y3z=14z=4\left\{ \begin{array} { r } x + 2 y + z = 0 \\y - 3 z = 1 \\4 z = - 4\end{array} \right.


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