State Whether the System of Equations Is Linear$\left\{ \begin{array} { r }
x + 2 y + z = 3 \
\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \
x + y + 4 z = - 4
\end{array} \right.$

Question

State Whether the System of Equations Is Linear$\left\{ \begin{array} { r } 
x + 2 y + z = 3 \
\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \
x + y + 4 z = - 4
\end{array} \right.$

Examlex · Accepted Answer

The Answer of State Whether the System of Equations Is Linear$\left\{ \begin{array} { r } 
x + 2 y + z = 3 \
\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \
x + y + 4 z = - 4
\end{array} \right.$

State Whether the System of Equations Is Linear $\left\{ \begin{array} { r } x + 2 y + z = 3 \\\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \\x + y + 4 z = - 4\end{array} \right.$

Definitions:

State Whether the System of Equations Is Linear {x+2y+z=32x+y−3z=1x+y+4z=−4\left\{ \begin{array} { r } x + 2 y + z = 3 \\\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \\x + y + 4 z = - 4\end{array} \right.⎩⎨⎧​x+2y+z=32​x+y−3​z=1x+y+4z=−4​

Definitions:

State Whether the System of Equations Is Linear $\left\{ \begin{array} { r } x + 2 y + z = 3 \\\sqrt { 2 } x + y - \sqrt { 3 } z = 1 \\x + y + 4 z = - 4\end{array} \right.$