State Whether the System of Equations Is Linear$$\left\{ \begin{array} { r }
x + \sqrt { 2 } y + z = 2 \
3 x + 2 y - z = 0 \
x + y + z ^ { 2 } + 2 = 1
\end{array} \right.$$

Question

State Whether the System of Equations Is Linear$$\left\{ \begin{array} { r } 
x + \sqrt { 2 } y + z = 2 \
3 x + 2 y - z = 0 \
x + y + z ^ { 2 } + 2 = 1
\end{array} \right.$$

Examlex · Accepted Answer

The Answer of State Whether the System of Equations Is Linear$$\left\{ \begin{array} { r } 
x + \sqrt { 2 } y + z = 2 \
3 x + 2 y - z = 0 \
x + y + z ^ { 2 } + 2 = 1
\end{array} \right.$$

State Whether the System of Equations Is Linear $\left\{ \begin{array} { r } x + \sqrt { 2 } y + z = 2 \\3 x + 2 y - z = 0 \\x + y + z ^ { 2 } + 2 = 1\end{array} \right.$

Definitions:

State Whether the System of Equations Is Linear {x+2y+z=23x+2y−z=0x+y+z2+2=1\left\{ \begin{array} { r } x + \sqrt { 2 } y + z = 2 \\3 x + 2 y - z = 0 \\x + y + z ^ { 2 } + 2 = 1\end{array} \right.⎩⎨⎧​x+2​y+z=23x+2y−z=0x+y+z2+2=1​

Definitions:

State Whether the System of Equations Is Linear $\left\{ \begin{array} { r } x + \sqrt { 2 } y + z = 2 \\3 x + 2 y - z = 0 \\x + y + z ^ { 2 } + 2 = 1\end{array} \right.$