Solve the System of Linear Equations$$\left\{ \begin{array} { r }
x + 3 y = 0 \
2 x + 7 y + 2 z = - 1 \
x + 4 y + 3 z = - 4
\end{array} \right.$$

Question

Solve the System of Linear Equations$$\left\{ \begin{array} { r } 
x + 3 y = 0 \
2 x + 7 y + 2 z = - 1 \
x + 4 y + 3 z = - 4
\end{array} \right.$$

Examlex · Accepted Answer

The Answer of Solve the System of Linear Equations$$\left\{ \begin{array} { r } 
x + 3 y = 0 \
2 x + 7 y + 2 z = - 1 \
x + 4 y + 3 z = - 4
\end{array} \right.$$

Solve the System of Linear Equations $\left\{ \begin{array} { r } x + 3 y = 0 \\2 x + 7 y + 2 z = - 1 \\x + 4 y + 3 z = - 4\end{array} \right.$

Definitions:

Solve the System of Linear Equations {x+3y=02x+7y+2z=−1x+4y+3z=−4\left\{ \begin{array} { r } x + 3 y = 0 \\2 x + 7 y + 2 z = - 1 \\x + 4 y + 3 z = - 4\end{array} \right.⎩⎨⎧​x+3y=02x+7y+2z=−1x+4y+3z=−4​

Definitions:

Solve the System of Linear Equations $\left\{ \begin{array} { r } x + 3 y = 0 \\2 x + 7 y + 2 z = - 1 \\x + 4 y + 3 z = - 4\end{array} \right.$