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The Tension of the Right-Hand String Divided by the Tension θ\theta

question 39

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   The tension of the right-hand string divided by the tension of the left-hand string is given by A)  sin  \theta <sub>2</sub> / sin  \theta <sub>1 </sub> B)  cos  \theta <sub>1</sub> / cos  \theta <sub>2 </sub> C)  cos  \theta <sub>2 </sub>/ cos  \theta <sub>1 </sub> D)  sin  \theta <sub>1</sub> / sin  \theta <sub>2 </sub> E)  (mg - T<sub>1</sub> sin  \theta <sub>1</sub>)  / (T<sub>1</sub>  \times  sin  \theta <sub>2</sub>)  The tension of the right-hand string divided by the tension of the left-hand string is given by


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