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Bernoulli's Equation for Nonviscous Flow Can Be Stated as
P1 ρ\rho

question 42

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Bernoulli's equation for nonviscous flow can be stated as
P1 + ρ\rho gy1 +  Bernoulli's equation for nonviscous flow can be stated as P<sub>1</sub> +  \rho gy<sub>1</sub> +    \rho v<sub>1</sub>2 = P<sub>2</sub> +  \rho gy<sub>2</sub> +    \rho v<sub>2</sub>2 A fluid is flowing through a horizontal tube that changes in cross-sectional area from A<sub>1</sub>= 0.75 cm<sup>2</sup> to A<sub>2</sub> = 0.030 cm<sup>2</sup>.   When v<sub>1</sub> = 3.5 cm/s,  \rho  = 1.4 g/cm<sup>3</sup>, and viscosity is neglected, the difference between pressure P<sub>2</sub> at A<sub>2</sub> and P<sub>1</sub> at A<sub>1</sub> is A)  54  \times  10<sup>3</sup> dyn/cm<sup>2</sup>, with P<sub>1</sub> higher. B)  59 dyn/cm<sup>2</sup>, with P<sub>2</sub> higher. C)  59 dyn/cm<sup>2</sup>, with P<sub>1</sub> higher. D)  8.3  \times  10<sup>2</sup> dyn/cm<sup>2</sup>, with P<sub>2</sub> higher. E)  None of these is correct. ρ\rho v12 = P2 + ρ\rho gy2 +  Bernoulli's equation for nonviscous flow can be stated as P<sub>1</sub> +  \rho gy<sub>1</sub> +    \rho v<sub>1</sub>2 = P<sub>2</sub> +  \rho gy<sub>2</sub> +    \rho v<sub>2</sub>2 A fluid is flowing through a horizontal tube that changes in cross-sectional area from A<sub>1</sub>= 0.75 cm<sup>2</sup> to A<sub>2</sub> = 0.030 cm<sup>2</sup>.   When v<sub>1</sub> = 3.5 cm/s,  \rho  = 1.4 g/cm<sup>3</sup>, and viscosity is neglected, the difference between pressure P<sub>2</sub> at A<sub>2</sub> and P<sub>1</sub> at A<sub>1</sub> is A)  54  \times  10<sup>3</sup> dyn/cm<sup>2</sup>, with P<sub>1</sub> higher. B)  59 dyn/cm<sup>2</sup>, with P<sub>2</sub> higher. C)  59 dyn/cm<sup>2</sup>, with P<sub>1</sub> higher. D)  8.3  \times  10<sup>2</sup> dyn/cm<sup>2</sup>, with P<sub>2</sub> higher. E)  None of these is correct. ρ\rho v22
A fluid is flowing through a horizontal tube that changes in cross-sectional area from
A1= 0.75 cm2 to A2 = 0.030 cm2.  Bernoulli's equation for nonviscous flow can be stated as P<sub>1</sub> +  \rho gy<sub>1</sub> +    \rho v<sub>1</sub>2 = P<sub>2</sub> +  \rho gy<sub>2</sub> +    \rho v<sub>2</sub>2 A fluid is flowing through a horizontal tube that changes in cross-sectional area from A<sub>1</sub>= 0.75 cm<sup>2</sup> to A<sub>2</sub> = 0.030 cm<sup>2</sup>.   When v<sub>1</sub> = 3.5 cm/s,  \rho  = 1.4 g/cm<sup>3</sup>, and viscosity is neglected, the difference between pressure P<sub>2</sub> at A<sub>2</sub> and P<sub>1</sub> at A<sub>1</sub> is A)  54  \times  10<sup>3</sup> dyn/cm<sup>2</sup>, with P<sub>1</sub> higher. B)  59 dyn/cm<sup>2</sup>, with P<sub>2</sub> higher. C)  59 dyn/cm<sup>2</sup>, with P<sub>1</sub> higher. D)  8.3  \times  10<sup>2</sup> dyn/cm<sup>2</sup>, with P<sub>2</sub> higher. E)  None of these is correct. When v1 = 3.5 cm/s, ρ\rho = 1.4 g/cm3, and viscosity is neglected, the difference between pressure P2 at A2 and P1 at A1 is


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