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When a Spring Is Stretched and Then Released, It Oscillates

question 17

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When a spring is stretched and then released, it oscillates according to two laws of physics: Hooke's Law and Netwon's Second Law. These two laws combine to form the following differential equation in the case of free, undamped oscillation: When a spring is stretched and then released, it oscillates according to two laws of physics: Hooke's Law and Netwon's Second Law. These two laws combine to form the following differential equation in the case of free, undamped oscillation:   where m is the mass of an object attached to the spring, x is the distance the spring is stretched beyond its standard length with the object attached (its equilibrium point) , t is time, and k is a constant associated with the strength of the spring. Consider a spring with   from which is hung a 40-pound weight. The spring with the weight attached stretches to its equilibrium point. The spring is then pulled 7 feet farther than its equilibrium and released. Find a particular solution for the position of the spring after time t. Use the fact that   , where g is the gravitational constant 32 feet per second per second, and that when the spring is first released, its velocity is zero. Round the coefficients to three decimal places. A)    B)    C)    D)    E)   where m is the mass of an object attached to the spring, x is the distance the spring is stretched beyond its standard length with the object attached (its equilibrium point) , t is time, and k is a constant associated with the strength of the spring. Consider a spring with When a spring is stretched and then released, it oscillates according to two laws of physics: Hooke's Law and Netwon's Second Law. These two laws combine to form the following differential equation in the case of free, undamped oscillation:   where m is the mass of an object attached to the spring, x is the distance the spring is stretched beyond its standard length with the object attached (its equilibrium point) , t is time, and k is a constant associated with the strength of the spring. Consider a spring with   from which is hung a 40-pound weight. The spring with the weight attached stretches to its equilibrium point. The spring is then pulled 7 feet farther than its equilibrium and released. Find a particular solution for the position of the spring after time t. Use the fact that   , where g is the gravitational constant 32 feet per second per second, and that when the spring is first released, its velocity is zero. Round the coefficients to three decimal places. A)    B)    C)    D)    E)   from which is hung a 40-pound weight. The spring with the weight attached stretches to its equilibrium point. The spring is then pulled 7 feet farther than its equilibrium and released. Find a particular solution for the position of the spring after time t. Use the fact that When a spring is stretched and then released, it oscillates according to two laws of physics: Hooke's Law and Netwon's Second Law. These two laws combine to form the following differential equation in the case of free, undamped oscillation:   where m is the mass of an object attached to the spring, x is the distance the spring is stretched beyond its standard length with the object attached (its equilibrium point) , t is time, and k is a constant associated with the strength of the spring. Consider a spring with   from which is hung a 40-pound weight. The spring with the weight attached stretches to its equilibrium point. The spring is then pulled 7 feet farther than its equilibrium and released. Find a particular solution for the position of the spring after time t. Use the fact that   , where g is the gravitational constant 32 feet per second per second, and that when the spring is first released, its velocity is zero. Round the coefficients to three decimal places. A)    B)    C)    D)    E)   , where g is the gravitational constant 32 feet per second per second, and that when the spring is first released, its velocity is zero. Round the coefficients to three decimal places.


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