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Using the Following Data,determine for the Electrochemical Cell Constructed \to

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Using the following data,determine  Using the following data,determine   for the electrochemical cell constructed using the reaction of nitrous oxide and oxalic acid under acidic conditions.Unbalanced: N<sub>2</sub>O(g) + H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>(s)  \to  2 CO<sub>2</sub>(g) + N<sub>2</sub>(g) + H<sub>2</sub>O(   )  Half-reaction Standard reduction potential 2 CO<sub>2</sub>(g) + 2 H<sup>+</sup>(aq) + 2 e<sup>-</sup>  \to  H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>(s) -0.49 N<sub>2</sub>O(g) + 2 H<sup>+</sup>(aq) + 2 e<sup>-</sup> \to  N<sub>2</sub>(g) + H<sub>2</sub>O(   ) +1.78 A)  +1.29 V  B)  -1.29 V  C)  +2.27 V  D)  -2.27 V  E)  +0.87 V  for the electrochemical cell constructed using the reaction of nitrous oxide and oxalic acid under acidic conditions.Unbalanced: N2O(g) + H2C2O4(s) \to 2 CO2(g) + N2(g) + H2O(  Using the following data,determine   for the electrochemical cell constructed using the reaction of nitrous oxide and oxalic acid under acidic conditions.Unbalanced: N<sub>2</sub>O(g) + H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>(s)  \to  2 CO<sub>2</sub>(g) + N<sub>2</sub>(g) + H<sub>2</sub>O(   )  Half-reaction Standard reduction potential 2 CO<sub>2</sub>(g) + 2 H<sup>+</sup>(aq) + 2 e<sup>-</sup>  \to  H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>(s) -0.49 N<sub>2</sub>O(g) + 2 H<sup>+</sup>(aq) + 2 e<sup>-</sup> \to  N<sub>2</sub>(g) + H<sub>2</sub>O(   ) +1.78 A)  +1.29 V  B)  -1.29 V  C)  +2.27 V  D)  -2.27 V  E)  +0.87 V  )
Half-reaction Standard reduction potential
2 CO2(g) + 2 H+(aq) + 2 e- \to H2C2O4(s) -0.49
N2O(g) + 2 H+(aq) + 2 e- \to N2(g) + H2O(  Using the following data,determine   for the electrochemical cell constructed using the reaction of nitrous oxide and oxalic acid under acidic conditions.Unbalanced: N<sub>2</sub>O(g) + H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>(s)  \to  2 CO<sub>2</sub>(g) + N<sub>2</sub>(g) + H<sub>2</sub>O(   )  Half-reaction Standard reduction potential 2 CO<sub>2</sub>(g) + 2 H<sup>+</sup>(aq) + 2 e<sup>-</sup>  \to  H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>(s) -0.49 N<sub>2</sub>O(g) + 2 H<sup>+</sup>(aq) + 2 e<sup>-</sup> \to  N<sub>2</sub>(g) + H<sub>2</sub>O(   ) +1.78 A)  +1.29 V  B)  -1.29 V  C)  +2.27 V  D)  -2.27 V  E)  +0.87 V  ) +1.78


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