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Calculate for an Electrochemical Cell Reaction That Occurs Under \to

question 113

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Calculate  Calculate   for an electrochemical cell reaction that occurs under acidic aqueous conditions based on the following two half-reactions for which the standard reduction potentials are given.Use the smallest whole-number coefficients possible when balancing the overall reaction.  Cr<sub>2</sub>O<sub>7</sub><sup>2-</sup> + 14 H<sup>+</sup> + 6 e<sup>-</sup> \to  2 Cr<sup>3+</sup> + 7 H<sub>2</sub>O  \quad    \quad  +1.33 V CH<sub>3</sub>COOH + 4 H<sup>+</sup> + 4 e<sup>-</sup> \to  C<sub>2</sub>H<sub>5</sub>OH + H<sub>2</sub>O   \quad  +0.058 V A)  -1610 kJ  B)  +1610 kJ  C)  -1470 kJ  D)  +2880 kJ  E)  -2880 kJ  for an electrochemical cell reaction that occurs under acidic aqueous conditions based on the following two half-reactions for which the standard reduction potentials are given.Use the smallest whole-number coefficients possible when balancing the overall reaction.
Cr2O72- + 14 H+ + 6 e- \to 2 Cr3+ + 7 H2O \quad \quad +1.33 V
CH3COOH + 4 H+ + 4 e- \to C2H5OH + H2O \quad +0.058 V


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