The Equilibrium Constant for the Formation of Calcium Carbonate from the Ions

question 115

Multiple Choice

The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2 $\times$ 10⁸ according to the reaction Ca²⁺(aq) + CO₃^2-(aq) $\leftrightarrows$ CaCO₃(s) .What is the value of the equilibrium constant for the reverse of this reaction?

• A)the same,2.2 \(\times\)10⁸
• B)-2.2 \(\times\) 10⁸
• C)2.2 \(\times\)10^-8
• D)4.5 \(\times\) 10^-9
• E)4.5 \(\times\) 10⁹

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