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The acetate ion,CH3COO-,reacts with water as a weak base: CH3COO-(aq) + H2O( ) CH3COOH(aq) + OH-(aq) ,with K = 5.7 10-10 at 25 C.If sodium acetate were dissolved in water to make a 0.50 M solution,what would be the resulting concentration of OH-?
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