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The Acetate Ion,CH3COO-,reacts with Water as a Weak Base: CH3COO-(aq) \leftrightarrows

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The acetate ion,CH3COO-,reacts with water as a weak base: CH3COO-(aq) + H2O(  The acetate ion,CH<sub>3</sub>COO<sup>-</sup>,reacts with water as a weak base: CH<sub>3</sub>COO<sup>-</sup>(aq) + H<sub>2</sub>O(   )  \leftrightarrows  CH<sub>3</sub>COOH(aq) + OH<sup>-</sup>(aq) ,with K = 5.7  \times 10<sup>-10</sup> at 25<sup> \circ </sup>C.If sodium acetate were dissolved in water to make a 0.50 M solution,what would be the resulting concentration of OH<sup>-</sup>? A) 0.50 M B) 1.7  \times 10<sup>-5</sup> M C) 0.25 M D) 1.1  \times  10<sup>-9</sup> M E) 2.9  \times  10<sup>-10</sup> M ) \leftrightarrows CH3COOH(aq) + OH-(aq) ,with K = 5.7 ×\times 10-10 at 25 \circ C.If sodium acetate were dissolved in water to make a 0.50 M solution,what would be the resulting concentration of OH-?


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