The Rate Constant for the First-Order Decomposition of a Particular $\times$

question 72

Multiple Choice

The rate constant for the first-order decomposition of a particular hydrocarbon is 1.85 $\times$ 10^-6 s^-1 at 485 K.If the activation energy is 84.0 kJ/mol,what is the value of the frequency factor at this temperature?

• A)4.85 \(\times\)10^-4 s^-1
• B)1.11 \(\times\)10⁹ s^-1
• C)2.2\(\times\)10¹ s^-1
• D)2.06 \(\times\)10³ s^-1
• E)1.81 \(\times\)10^-6 s^-1