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Potassium Superoxide (KO2,71 \to 4 KOH(s)+ 3 O2(g)
A)225

question 124

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Potassium superoxide (KO2,71.10 g/mol) can be used to generate oxygen gas.What is the theoretical yield of O2 (32.00 g/mol) if 500.0 g KO2 reacts with excess H2O (18.02 g/mol) ? 4 KO2(s) + 2 H2O  Potassium superoxide (KO<sub>2</sub>,71.10 g/mol) can be used to generate oxygen gas.What is the theoretical yield of O<sub>2</sub> (32.00 g/mol) if 500.0 g KO<sub>2</sub> reacts with excess H<sub>2</sub>O (18.02 g/mol) ? 4 KO<sub>2</sub>(s) + 2 H<sub>2</sub>O    \to  4 KOH(s) + 3 O<sub>2</sub>(g)  A) 225.0 g B) 168.8 g C) 375.0 g D) 675.1g E) 56.26 g \to 4 KOH(s) + 3 O2(g)


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