Consider the Following Standard Heats of Formation:
P₄O₁₀(s)= -3110 KJ/mol $\to$

question 70

Short Answer

Consider the following standard heats of formation:
P₄O₁₀(s)= -3110 kJ/mol
H₂O(l)= -286 kJ/mol
H₃PO₄(s)= -1279 kJ/mol
Calculate the change in enthalpy for the following process:
P₄O₁₀(s)+ 6H₂O(l) $\to$ 4H₃PO₄(s)

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