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The Following Equation Describes the Oxidation of Ethanol to Acetic

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The following equation describes the oxidation of ethanol to acetic acid by potassium permanganate: The following equation describes the oxidation of ethanol to acetic acid by potassium permanganate:   5.00 g of ethanol and an excess of aqueous KMnO<sub>4</sub> are reacted,and 4.24 g of HC<sub>2</sub>H<sub>3</sub>O<sub>2</sub> result.What is the percent yield? A) 100% B) 65.1% C) 21.7% D) 34.9% E) 4.24 g HC<sub>2</sub>H<sub>3</sub>O<sub>2</sub> is impossible since it represents more than 100% yield. 5.00 g of ethanol and an excess of aqueous KMnO4 are reacted,and 4.24 g of HC2H3O2 result.What is the percent yield?

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