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Refer to the Galvanic Cell Below (The Contents of Each \to

question 131

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Refer to the galvanic cell below (the contents of each half-cell are written beneath each compartment) :  Refer to the galvanic cell below (the contents of each half-cell are written beneath each compartment) :   0.10 M MnO<sub>4</sub><sup>-</sup> 0.40 M Cr<sup>3+</sup> 0.20 M Mn<sup>2+</sup> 0.30 M Cr<sub>2</sub>O<sub>7</sub><sup>2</sup><sup>-</sup> 0.010 M H<sup>+ </sup> 0.010 M H<sup>+</sup> The standard reduction potentials are as follows: MnO<sub>4</sub><sup>-</sup> + 8H<sup>+</sup> + 5e<sup>-</sup>  \to  Mn<sup>2+</sup> + 4H<sub>2</sub>O, \varepsilon <sup> \circ </sup> = 1.506 V Cr<sub>2</sub>O<sub>7</sub><sup>2</sup><sup>-</sup> + 14H<sup>+</sup> + 6e<sup>-</sup>  \to  2Cr<sup>3+</sup> + 7H<sub>2</sub>O, \varepsilon <sup> \circ </sup> = 1.330 V What is the value of  \varepsilon <sup> \circ </sup> <sub>cell</sub>? A) -0.176 B) 2.836 C) 0.176 D) 0.676 E) 6.200 0.10 M MnO4- 0.40 M Cr3+ 0.20 M Mn2+ 0.30 M Cr2O72-
0.010 M H+ 0.010 M H+
The standard reduction potentials are as follows:
MnO4- + 8H+ + 5e- \to Mn2+ + 4H2O, ε\varepsilon \circ = 1.506 V
Cr2O72- + 14H+ + 6e- \to 2Cr3+ + 7H2O, ε\varepsilon \circ = 1.330 V
What is the value of ε\varepsilon \circ cell?


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