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A cell is set up with copper and lead electrodes in contact with CuSO4(aq) and Pb(NO3) 2(aq) ,respectively,at 25°C.The standard reduction potentials are: Pb2+ + 2e- Pb = -0.13 V
Cu2+ + 2e- Cu = +0.34 V
If the Pb2+ and Cu2+ are each 1.0 M,the potential of the cell,in volts,is:
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