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The Cation M2+ Reacts with NH3 to Form a Series ×\times

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The cation M2+ reacts with NH3 to form a series of complex ions as follows: M2+ + NH3
 The cation M<sup>2+</sup> reacts with NH<sub>3</sub> to form a series of complex ions as follows: M<sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sup>2+</sup> K<sub>1</sub> = 10<sup>2</sup> M(NH<sub>3</sub>) <sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> K<sub>2</sub> = 10<sup>3</sup> M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sub>3</sub><sup>2+</sup> K<sub>3</sub> = 10<sup>2</sup> A 1.0  \times 10<sup>-</sup><sup>3</sup> mol sample of M(NO<sub>3</sub>) <sub>2 </sub>is added to 1.0 L of 15.0 M NH<sub>3</sub> (K<sub>b</sub> = 1.8  \times  10<sup>-</sup><sup>5</sup>) .Choose the dominant species in this solution. A) M<sup>2+</sup> B) M(NH<sub>3</sub>) <sup>2+</sup> C) M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> D) M(NH<sub>3</sub>) <sub>3</sub><sup>2+</sup> E) M(NO<sub>3</sub>) <sub>2</sub> M(NH3) 2+
K1 = 102
M(NH3) 2+ + NH3
 The cation M<sup>2+</sup> reacts with NH<sub>3</sub> to form a series of complex ions as follows: M<sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sup>2+</sup> K<sub>1</sub> = 10<sup>2</sup> M(NH<sub>3</sub>) <sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> K<sub>2</sub> = 10<sup>3</sup> M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sub>3</sub><sup>2+</sup> K<sub>3</sub> = 10<sup>2</sup> A 1.0  \times 10<sup>-</sup><sup>3</sup> mol sample of M(NO<sub>3</sub>) <sub>2 </sub>is added to 1.0 L of 15.0 M NH<sub>3</sub> (K<sub>b</sub> = 1.8  \times  10<sup>-</sup><sup>5</sup>) .Choose the dominant species in this solution. A) M<sup>2+</sup> B) M(NH<sub>3</sub>) <sup>2+</sup> C) M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> D) M(NH<sub>3</sub>) <sub>3</sub><sup>2+</sup> E) M(NO<sub>3</sub>) <sub>2</sub> M(NH3) 22+
K2 = 103
M(NH3) 22+ + NH3
 The cation M<sup>2+</sup> reacts with NH<sub>3</sub> to form a series of complex ions as follows: M<sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sup>2+</sup> K<sub>1</sub> = 10<sup>2</sup> M(NH<sub>3</sub>) <sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> K<sub>2</sub> = 10<sup>3</sup> M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> + NH<sub>3</sub> <sub> </sub>   M(NH<sub>3</sub>) <sub>3</sub><sup>2+</sup> K<sub>3</sub> = 10<sup>2</sup> A 1.0  \times 10<sup>-</sup><sup>3</sup> mol sample of M(NO<sub>3</sub>) <sub>2 </sub>is added to 1.0 L of 15.0 M NH<sub>3</sub> (K<sub>b</sub> = 1.8  \times  10<sup>-</sup><sup>5</sup>) .Choose the dominant species in this solution. A) M<sup>2+</sup> B) M(NH<sub>3</sub>) <sup>2+</sup> C) M(NH<sub>3</sub>) <sub>2</sub><sup>2+</sup> D) M(NH<sub>3</sub>) <sub>3</sub><sup>2+</sup> E) M(NO<sub>3</sub>) <sub>2</sub> M(NH3) 32+
K3 = 102
A 1.0 ×\times 10-3 mol sample of M(NO3) 2 is added to 1.0 L of 15.0 M NH3 (Kb = 1.8 ×\times 10-5) .Choose the dominant species in this solution.

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