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The Following Questions Refer to the Following System: 500 $\times$ 10³
[Mn(C₂O₄)₂]²^-
MnC₂O₄+ C₂O₄²^-
K₂ =

question 64

Multiple Choice

The following questions refer to the following system: 500.0 mL of 0.020 M Mn(NO₃) ₂ are mixed with 1.0 L of 1.0 M Na₂C₂O₄.The oxalate ion,C₂O₄,acts as a ligand to form a complex ion with the Mn²⁺ ion with a coordination number of two.
Mn²⁺ + C₂O₄²^-
$The following questions refer to the following system: 500.0 mL of 0.020 M Mn(NO3) 2 are mixed with 1.0 L of 1.0 M Na2C2O4.The oxalate ion,C2O4,acts as a ligand to form a complex ion with the Mn2+ ion with a coordination number of two. Mn2+ + C2O42- MnC2O4 K1 = 7.9 \times 103 [Mn(C2O4) 2]2- MnC2O4 + C2O42- K2 = 1.26 \times 10-2 -Find the equilibrium concentration of Mn(C2O4) in the system. A) 9.2 \times 10-5 M B) 0.01 M C) 2.5 \times 10-8 M D) 1.3 \times 10-4 M E) 6.7 \times 10-3 M$ MnC₂O₄
K₁ = 7.9 $\times$ 10³
[Mn(C₂O₄) ₂]²^-
$The following questions refer to the following system: 500.0 mL of 0.020 M Mn(NO3) 2 are mixed with 1.0 L of 1.0 M Na2C2O4.The oxalate ion,C2O4,acts as a ligand to form a complex ion with the Mn2+ ion with a coordination number of two. Mn2+ + C2O42- MnC2O4 K1 = 7.9 \times 103 [Mn(C2O4) 2]2- MnC2O4 + C2O42- K2 = 1.26 \times 10-2 -Find the equilibrium concentration of Mn(C2O4) in the system. A) 9.2 \times 10-5 M B) 0.01 M C) 2.5 \times 10-8 M D) 1.3 \times 10-4 M E) 6.7 \times 10-3 M$ MnC₂O₄+ C₂O₄²^-
K₂ = 1.26 $\times$ 10^-²
-Find the equilibrium concentration of Mn(C₂O₄) in the system.

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Fixed Overhead

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Materials Price Variance

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The Following Questions Refer to the Following System: 500 ×\times× 103 [Mn(C2O4)2]2- MnC2O4 + C2O42- K2 =

Definitions:

The Following Questions Refer to the Following System: 500 $\times$ 10³
[Mn(C₂O₄)₂]²^-
MnC₂O₄+ C₂O₄²^-
K₂ =