What Is the Equilibrium PH of a 0 $\times$ 10^-3,K_a2 = 6

question 21

Multiple Choice

What is the equilibrium pH of a 0.835 M solution of H₃PO₄(aq) ? (K_a1 = 7.5 $\times$ 10^-3,K_a2 = 6.2 $\times$ 10^-8,K_a3 = 4.8 $\times$ 10^-13)

• A)1.12
• B)3.64
• C)12.32
• D)6.20
• E)7.21

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