Find a Unit Vector Perpendicular to the Plane X - $\left( - \frac { 2 } { 3 } , - \frac { 2 } { 3 } , \frac { 1 } { 3 } \right)$

question 118

Multiple Choice

Find a unit vector perpendicular to the plane x - 2y - 2z = 10.

• A) \(\left( - \frac { 2 } { 3 } , - \frac { 2 } { 3 } , \frac { 1 } { 3 } \right)\)
• B) \(\left( - \frac { 1 } { 3 } , \frac { 2 } { 3 } , \frac { 2 } { 3 } \right)\)
• C) \(\left\langle \frac { 1 } { 3 } , \frac { 2 } { 3 } , \frac { 2 } { 3 } \right\}\)
• D) \(\left\langle \frac { 2 } { 3 } , \frac { 2 } { 3 } , \frac { 1 } { 3 } \right\}\)
• E) \(\left( \frac { 1 } { \sqrt { 2 } } , \frac { 1 } { \sqrt { 2 } } , 0 \right)\)
• F) \(\left( \frac { 1 } { \sqrt { 2 } } , 0 , \frac { 1 } { \sqrt { 2 } } \right)\)
• G) \(\left( 0 , \frac { 1 } { \sqrt { 2 } } , \frac { 1 } { \sqrt { 2 } } \right)\)
• H) \(\{ - 1,0,0 \}\)

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