Is It True That$\int \sqrt { 4 - x ^ { 2 } } d x = \frac { x } { 2 } \sqrt { 4 - x ^ { 2 } } + \arcsin \left( \frac { x } { 2 } \right) + C$

Question

Examlex · Accepted Answer

The Answer of Is It True That$\int \sqrt { 4 - x ^ { 2 } } d x = \frac { x } { 2 } \sqrt { 4 - x ^ { 2 } } + \arcsin \left( \frac { x } { 2 } \right) + C$

Is It True That $\int \sqrt { 4 - x ^ { 2 } } d x = \frac { x } { 2 } \sqrt { 4 - x ^ { 2 } } + \arcsin \left( \frac { x } { 2 } \right) + C$

Definitions:

Is It True That ∫4−x2dx=x24−x2+arcsin⁡(x2)+C\int \sqrt { 4 - x ^ { 2 } } d x = \frac { x } { 2 } \sqrt { 4 - x ^ { 2 } } + \arcsin \left( \frac { x } { 2 } \right) + C∫4−x2​dx=2x​4−x2​+arcsin(2x​)+C

Definitions:

Is It True That $\int \sqrt { 4 - x ^ { 2 } } d x = \frac { x } { 2 } \sqrt { 4 - x ^ { 2 } } + \arcsin \left( \frac { x } { 2 } \right) + C$