Given $f ( x ) = x ^ { 3 } + 2 x - 4$

question 171

Multiple Choice

Given $f ( x ) = x ^ { 3 } + 2 x - 4$ , use Newton's method to find the iterative formula for $x _ { n + 1 }$ .

• A) \(x _ { n + 1 } = - \frac { x _ { n } ^ { 3 } + 2 x _ { n } } { 3 x _ { n } ^ { 2 } + 2 }\)
• B) \(x _ { n + 1 } = x _ { n } - \frac { x _ { n } ^ { 3 } + 2 x _ { n } } { 3 x _ { n } ^ { 2 } + 2 }\)
• C) \(x _ { n + 1 } = x _ { n } - \frac { x _ { n } ^ { 3 } + 2 x _ { n } - 4 } { 3 x _ { n } ^ { 2 } + 2 }\)
• D) \(x _ { n + 1 } = x _ { n } + \frac { 3 } { x _ { n } }\)
• E) \(x _ { n + 1 } = \frac { x _ { n } ^ { 3 } + 2 x _ { n } } { 3 x _ { n } ^ { 2 } + 2 }\)
• F) \(x _ { n + 1 } = x _ { n } + \frac { x _ { n } ^ { 3 } + 2 x _ { n } } { 3 x _ { n } ^ { 2 } + 2 }\)
• G) \(x _ { n + 1 } = x _ { n } + \frac { x _ { n } ^ { 3 } + 2 x _ { n } - 4 } { 3 x _ { n } ^ { 2 } + 2 }\)
• H)None of these

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