Find the Surface Area of the Part of the Cone $z = \left( x ^ { 2 } + y ^ { 2 } \right) ^ { 1 / 2 }$

question 96

Short Answer

Find the surface area of the part of the cone $z = \left( x ^ { 2 } + y ^ { 2 } \right) ^ { 1 / 2 }$ lying inside the cylinder $x ^ { 2 } - 2 x + y ^ { 2 } = 0$ .