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Calculate the Equilibrium Constant at 500 K for the Following

question 157

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Calculate the equilibrium constant at 500 K for the following reaction given the data below. Calculate the equilibrium constant at 500 K for the following reaction given the data below.       K <sub>c </sub>(298 K)  <font face= symbol ></font> 6.1 <font face= symbol ></font> 10<sup>5</sup>   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>16.5 kJ/mol   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>4</sup> E) 332 Calculate the equilibrium constant at 500 K for the following reaction given the data below.       K <sub>c </sub>(298 K)  <font face= symbol ></font> 6.1 <font face= symbol ></font> 10<sup>5</sup>   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>16.5 kJ/mol   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>4</sup> E) 332 Calculate the equilibrium constant at 500 K for the following reaction given the data below.       K <sub>c </sub>(298 K)  <font face= symbol ></font> 6.1 <font face= symbol ></font> 10<sup>5</sup>   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>16.5 kJ/mol   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>4</sup> E) 332 K c (298 K) 6.1 105 Calculate the equilibrium constant at 500 K for the following reaction given the data below.       K <sub>c </sub>(298 K)  <font face= symbol ></font> 6.1 <font face= symbol ></font> 10<sup>5</sup>   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>16.5 kJ/mol   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>4</sup> E) 332 (NH3, g) 16.5 kJ/mol Calculate the equilibrium constant at 500 K for the following reaction given the data below.       K <sub>c </sub>(298 K)  <font face= symbol ></font> 6.1 <font face= symbol ></font> 10<sup>5</sup>   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>16.5 kJ/mol   (NH<sub>3</sub>, g)  <font face= symbol ></font> <font face= symbol ></font>46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>4</sup> E) 332 (NH3, g) 46.1 kJ/mol


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