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Given the Following Reactions and Associated Equilibrium Constants

question 37

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Given the following reactions and associated equilibrium constants Given the following reactions and associated equilibrium constants     2NO(g)  K<sub>1 </sub><font face= symbol ></font> 1.70 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g)  K<sub>2 </sub><font face= symbol ></font> 6.83 <font face= symbol ></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g)  <font face= symbol ></font> 3O<sub>2</sub>(g)    4NO<sub>2</sub>(g)  K<sub>new </sub><font face= symbol ></font> ? A) 1.59 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> B) 9.29 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>18</sup> C) 40.3 D) 62.9 E) 1.08 <font face= symbol ></font> 10<sup>17</sup> Given the following reactions and associated equilibrium constants     2NO(g)  K<sub>1 </sub><font face= symbol ></font> 1.70 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g)  K<sub>2 </sub><font face= symbol ></font> 6.83 <font face= symbol ></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g)  <font face= symbol ></font> 3O<sub>2</sub>(g)    4NO<sub>2</sub>(g)  K<sub>new </sub><font face= symbol ></font> ? A) 1.59 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> B) 9.29 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>18</sup> C) 40.3 D) 62.9 E) 1.08 <font face= symbol ></font> 10<sup>17</sup> 2NO(g) K1 1.70 1013 Given the following reactions and associated equilibrium constants     2NO(g)  K<sub>1 </sub><font face= symbol ></font> 1.70 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g)  K<sub>2 </sub><font face= symbol ></font> 6.83 <font face= symbol ></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g)  <font face= symbol ></font> 3O<sub>2</sub>(g)    4NO<sub>2</sub>(g)  K<sub>new </sub><font face= symbol ></font> ? A) 1.59 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> B) 9.29 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>18</sup> C) 40.3 D) 62.9 E) 1.08 <font face= symbol ></font> 10<sup>17</sup> Given the following reactions and associated equilibrium constants     2NO(g)  K<sub>1 </sub><font face= symbol ></font> 1.70 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g)  K<sub>2 </sub><font face= symbol ></font> 6.83 <font face= symbol ></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g)  <font face= symbol ></font> 3O<sub>2</sub>(g)    4NO<sub>2</sub>(g)  K<sub>new </sub><font face= symbol ></font> ? A) 1.59 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> B) 9.29 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>18</sup> C) 40.3 D) 62.9 E) 1.08 <font face= symbol ></font> 10<sup>17</sup> NO2(g)
K2 6.83 106
What is the equilibrium constant for the following reaction?
2N2O(g) 3O2(g) Given the following reactions and associated equilibrium constants     2NO(g)  K<sub>1 </sub><font face= symbol ></font> 1.70 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>13</sup>     NO<sub>2</sub>(g)  K<sub>2 </sub><font face= symbol ></font> 6.83 <font face= symbol ></font> 10<sup>6</sup> What is the equilibrium constant for the following reaction? 2N<sub>2</sub>O(g)  <font face= symbol ></font> 3O<sub>2</sub>(g)    4NO<sub>2</sub>(g)  K<sub>new </sub><font face= symbol ></font> ? A) 1.59 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>2</sup> B) 9.29 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>18</sup> C) 40.3 D) 62.9 E) 1.08 <font face= symbol ></font> 10<sup>17</sup> 4NO2(g) Knew ?


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