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The Equilibrium Constant for the Reaction Below Is 17

question 107

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The equilibrium constant for the reaction below is 17.5.
S(s) 3O2(g) The equilibrium constant for the reaction below is 17.5. S(s) <font face= symbol ></font> 3O<sub>2</sub>(g)   2SO<sub>3</sub>(g) What is the value of the equilibrium constant for the following reaction? 6SO<sub>3</sub>(g)   3S(s) <font face= symbol ></font> 9O<sub>2</sub>(g) 2SO3(g)
What is the value of the equilibrium constant for the following reaction?
6SO3(g) The equilibrium constant for the reaction below is 17.5. S(s) <font face= symbol ></font> 3O<sub>2</sub>(g)   2SO<sub>3</sub>(g) What is the value of the equilibrium constant for the following reaction? 6SO<sub>3</sub>(g)   3S(s) <font face= symbol ></font> 9O<sub>2</sub>(g) 3S(s) 9O2(g)


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