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Use the Following Information to Determine the Enthalpy for the Reaction

question 21

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Use the following information to determine the enthalpy for the reaction shown below. CS2(l) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) 3O2(g) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) CO2(g) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) 2SO2(g) H ?
C(graphite) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) O2(g) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) CO2(g) H 393.5 kJ
S(s) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) O2(g) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) SO2(g) H 296.8 kJ
C(graphite) 2S(s) Use the following information to determine the enthalpy for the reaction shown below. CS<sub>2</sub>(l)    <font face= symbol ></font>3O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)    <font face= symbol ></font>2SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> ? C(graphite)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>CO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>393.5 kJ S(s)    <font face= symbol ></font>O<sub>2</sub>(g)    <font face= symbol ></font>SO<sub>2</sub>(g)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> <font face= symbol ></font>296.8 kJ C(graphite)  <font face= symbol ></font> 2S(s)    <font face= symbol ></font>CS<sub>2</sub>(l)  <font face= symbol ></font>H<font face= symbol ></font> <font face= symbol ></font> 87.9 kJ A) (<font face= symbol ></font>1075 kJ)  B) (<font face= symbol ></font>1075 kJ)  C) (<font face= symbol ></font>778 kJ)  D) (<font face= symbol ></font>778 kJ)  E) (<font face= symbol ></font>602 kJ) CS2(l) H 87.9 kJ

Identify how regulatory changes can influence technological adoption and market forces.
Understand the concept of electronic commerce and its forms.
Comprehend the role of internet-based technologies in facilitating communication within organizations and with external partners.
Identify and distinguish between various forms of market competition.

Definitions:

Underproduction

A situation where the quantity produced of a good or service is less than the socially optimal level, often leading to market failure.

Market Price

The existing cost for acquiring or offloading an asset or service in the marketplace.

Consumer Surplus

The difference between the maximum price consumers are willing to pay and the actual price they pay.

Deadweight Loss

A loss of economic efficiency that occurs when the equilibrium for a good or service is not achieved or is not achievable due to market distortions like taxes or subsidies.

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