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Different Concentrations of Ions on Either Side of a Cell

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Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below. A cell must expend energy to maintain this concentration gradient by moving ions from one side of the membrane to the other. How much energy must be expended to transport 1 mole of sodium ions across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C (body temperature)?
(Given: Na+ + e- a, Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below. A cell must expend energy to maintain this concentration gradient by moving ions from one side of the membrane to the other. How much energy must be expended to transport 1 mole of sodium ions across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C (body temperature)? (Given: Na<sup>+</sup> + e<sup>-</sup> <font face= symbol ></font><font face= symbol ></font>a,<font face= symbol ></font>   = -2.71 V; F = 96,485 C; 1 J = 1 C V; R = 8.315 J / mol K)  = -2.71 V; F = 96,485 C; 1 J = 1 C V; R = 8.315 J / mol K) Different concentrations of ions on either side of a cell membrane constitute a concentration cell, which is described by the Nernst equation given below. A cell must expend energy to maintain this concentration gradient by moving ions from one side of the membrane to the other. How much energy must be expended to transport 1 mole of sodium ions across a membrane when the sodium ion concentration is 0.10 M on one side of the membrane and 0.010 M on the other side, and the temperature is 37°C (body temperature)? (Given: Na<sup>+</sup> + e<sup>-</sup> <font face= symbol ></font><font face= symbol ></font>a,<font face= symbol ></font>   = -2.71 V; F = 96,485 C; 1 J = 1 C V; R = 8.315 J / mol K)


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