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Calculate the Equilibrium Constant at 500 K for the Following

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Calculate the equilibrium constant at 500 K for the following reaction given the data below.
N2(g) + 3H2(g) Calculate the equilibrium constant at 500 K for the following reaction given the data below. N<sub>2</sub>(g) + 3H<sub>2</sub>(g)   2NH<sub>3</sub>(g) K<sub>c</sub>(298 K) = 6.1 <font face= symbol ></font> 10<sup>5</sup> <font face= symbol ></font>G   (NH<sub>3</sub>,g) = -16.5 kJ/mol <font face= symbol ></font>H   (NH<sub>3</sub>,g) = -46.1 kJ/mol 2NH3(g)
Kc(298 K) = 6.1 105
G Calculate the equilibrium constant at 500 K for the following reaction given the data below. N<sub>2</sub>(g) + 3H<sub>2</sub>(g)   2NH<sub>3</sub>(g) K<sub>c</sub>(298 K) = 6.1 <font face= symbol ></font> 10<sup>5</sup> <font face= symbol ></font>G   (NH<sub>3</sub>,g) = -16.5 kJ/mol <font face= symbol ></font>H   (NH<sub>3</sub>,g) = -46.1 kJ/mol (NH3,g) = -16.5 kJ/mol
H Calculate the equilibrium constant at 500 K for the following reaction given the data below. N<sub>2</sub>(g) + 3H<sub>2</sub>(g)   2NH<sub>3</sub>(g) K<sub>c</sub>(298 K) = 6.1 <font face= symbol ></font> 10<sup>5</sup> <font face= symbol ></font>G   (NH<sub>3</sub>,g) = -16.5 kJ/mol <font face= symbol ></font>H   (NH<sub>3</sub>,g) = -46.1 kJ/mol (NH3,g) = -46.1 kJ/mol


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