When [Ni(NH₃)₄]²⁺ Is Treated with Concentrated HCl, Two Compounds Having

question 16

Multiple Choice

When [Ni(NH₃) ₄]²⁺ is treated with concentrated HCl, two compounds having the same formula, Ni(NH₃) ₄Cl₂, designated I and II, are formed. Compound I can be converted to compound II by boiling it in dilute HCl. A solution of I reacts with oxalic acid, H₂C₂O₄, to form Ni(NH₃) ₄(C₂O₄) . Compound II does not react with oxalic acid. Compound II is:

• A) the cis isomer
• B) tetrahedral in shape
• C) the trans isomer
• D) the same as compound I
• E) octahedral in shape

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