Determine E°cell for the Reaction: Pb + Zn²⁺ → Pb²⁺

question 72

Multiple Choice

Determine E°cell for the reaction: Pb + Zn²⁺ → Pb²⁺ + Zn. The half reactions are: Pb2+(aq) + 2 e- → Pb(s)   E° = -0.125 V
Zn²⁺(aq) + 2 e- → Zn(s)   E° = -0.763 V

• A) 0.638 V
• B) -0.638 V
• C) 0.888 V
• D) -1.276 V
• E) -0.888 V

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