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Determine E°cell for the reaction: MnO4- + 8 H+ + 5 Fe2+ → Mn2+ + 4 H2O + 5 Fe3+. The half reactions are: Fe3+(aq) + e- → Fe2+(aq) E° = +0.771 V
MnO4-(aq) + 8 H+(aq) + 5 e- → Mn2+(aq) + 4 H2O(l) E° = 1.507 V
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