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Given the following half-reactions occurring in the silver-zinc hearing aid battery, calculate the voltage at 25°C of this battery.
ZnO(s) + H2O(l) + 2 e- → Zn(s) + 2 OH- E° = -1.260 V
Ag2O(s) + H2O(l) + 2 e- → 2 Ag(s) + 2 OH- E° = +0.342 V
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