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Determine E°cell for the Reaction: Pb + Cu2+ → Pb2

question 38

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Determine E°cell for the reaction: Pb + Cu2+ → Pb2+ + Cu. The half reactions are: Pb2+(aq) + 2 e- → Pb(s) E° = -0.125 V
Cu2+ + 2 e- → Cu E° = 0.340 V


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