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Conversion Factors for the Cumulative Average Number of Direct Labor

question 6

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Conversion Factors for the Cumulative Average Number of Direct Labor Hours per Unit
80% Learning Rate  ( n= cumulative production)  nnn11.00000190.53718370.4397620.90000200.52425380.4363430.83403210.51715390.4330440.78553220.51045400.4298450.74755230.50410640.3738260.71657240.498081280.3026970.69056250.492342560.2440580.66824260.486885120.1962290.64876270.481676000.18661100.63154280.476687000.17771110.61613290.471918000.17034120.60224300.467339000.16408130.58960310.462931,0000.15867140.57802320.458711,2000.14972150.56737330.464641,4000.14254160.55751340.450721,6000.13660170.54834350.446941,8000.13155180.53979360.443292,0000.1272090% Learning Rate  ( n= cumulative production)  nnn11.00000190.73545370.6709120.95000200.73039380.6683930.91540210.72559390.6659540.88905220.72102400.6635750.86784230.71666640.6204360.85013240.712511280.5606970.83496250.708532560.5058680.82172260.704725120.4559490.80998270.701066000.44519100.79945280.697547000.43496110.78991290.694168000.42629120.78120300.690909000.41878130.77320310.687751,0000.41217140.76580320.674711,2000.40097150.75891330.681771,4000.39173160.75249340.678931,6000.38390170.74646350.676171,8000.37711180.74080360.673502,0000.37114\begin{array}{c}\begin{array}{c}80 \% \text { Learning Rate }\\\text { ( } n=\text { cumulative production) }\\\begin{array}{rrrrrr}\hline n & & n & & {n} & \\\hline 1 & 1.00000 & 19 & 0.53718 & 37 & 0.43976 \\2 & 0.90000 & 20 & 0.52425 & 38 & 0.43634 \\3 & 0.83403 & 21 & 0.51715 & 39 & 0.43304 \\4 & 0.78553 & 22 & 0.51045 & 40 & 0.42984 \\5 & 0.74755 & 23 & 0.50410 & 64 & 0.37382 \\6 & 0.71657 & 24 & 0.49808 & 128 & 0.30269 \\7 & 0.69056 & 25 & 0.49234 & 256 & 0.24405 \\8 & 0.66824 & 26 & 0.48688 & 512 & 0.19622 \\9 & 0.64876 & 27 & 0.48167 & 600 & 0.18661 \\10 & 0.63154 & 28 & 0.47668 & 700 & 0.17771 \\11 & 0.61613 & 29 & 0.47191 & 800 & 0.17034 \\12 & 0.60224 & 30 & 0.46733 & 900 & 0.16408 \\13 & 0.58960 & 31 & 0.46293 & 1,000 & 0.15867 \\14 & 0.57802 & 32 & 0.45871 & 1,200 & 0.14972 \\15 & 0.56737 & 33 & 0.46464 & 1,400 & 0.14254 \\16 & 0.55751 & 34 & 0.45072 & 1,600 & 0.13660 \\17 & 0.54834 & 35 & 0.44694 & 1,800 & 0.13155\\18& 0.53979 & 36 & 0.44329 & 2,000 & 0.12720\end{array}\end{array}\begin{array}{cl}90 \% \text { Learning Rate }\\\text { ( } n=\text { cumulative production) }\\\begin{array}{rrrrrr}\hline n &&{n} & &n & \\\hline 1 & 1.00000 & 19 & 0.73545 & 37 & 0.67091 \\2 & 0.95000 & 20 & 0.73039 & 38 & 0.66839 \\3 & 0.91540 & 21 & 0.72559 & 39 & 0.66595 \\4 & 0.88905 & 22 & 0.72102 & 40 & 0.66357 \\5 & 0.86784 & 23 & 0.71666 & 64 & 0.62043 \\6 & 0.85013 & 24 & 0.71251 & 128 & 0.56069 \\7 & 0.83496 & 25 & 0.70853 & 256 & 0.50586 \\8 & 0.82172 & 26 & 0.70472 & 512 & 0.45594 \\9 & 0.80998 & 27 & 0.70106 & 600 & 0.44519 \\10 & 0.79945 & 28 & 0.69754 & 700 & 0.43496 \\11 & 0.78991 & 29 & 0.69416 & 800 & 0.42629 \\12 & 0.78120 & 30 & 0.69090 & 900 & 0.41878 \\13 & 0.77320 & 31 & 0.68775 & 1,000 & 0.41217 \\14 & 0.76580 & 32 & 0.67471 & 1,200 & 0.40097 \\15 & 0.75891 & 33 & 0.68177 & 1,400 & 0.39173 \\16 & 0.75249 & 34 & 0.67893 & 1,600 & 0.38390 \\17 & 0.74646 & 35 & 0.67617 & 1,800 & 0.37711 \\18 & 0.74080 & 36 & 0.67350 & 2,000 & 0.37114\end{array}\end{array}\end{array}

-Suppose the average time for the first 1,000 units you have manufactured is 2.375 minutes.Your rate of learning is 90 percent,and you need to find the total time required to manufacture the next 1,000 units.Refer to the copy of Table G.1 above.The total time is:

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