Consider the Combustion Reaction of Propane: C₃H₈(g)+ 5 O₂(g) $\rightarrow$ 3 CO₂(g)+ 4 H₂O(g), Where

question 87

Multiple Choice

Consider the combustion reaction of propane: C₃H₈(g) + 5 O₂(g) $\rightarrow$ 3 CO₂(g) + 4 H₂O(g) , where $\Delta$ H = -531 kcal. If 1.24 × 10⁵ kcal of energy is released in the reaction, how many moles of propane were burned?

• A)234 mol of C₃H₈
• B)6.58 × 10⁷ mol of C₃H₈
• C)0.00428 mol of C₃H₈
• D)0.0179 mol of C₃H₈

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