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A Solution Is Formed by Mixing 50

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A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 10-3 M CuNO3. Cu(I) forms complex ions with cyanide as follows: A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 <font face= symbol ></font> 10<sup>-3</sup> M CuNO<sub>3</sub>. Cu(I)  forms complex ions with cyanide as follows:   Calculate the following concentrations at equilibrium: -[Cu(CN) <sub>2</sub><sup>-</sup>] A)  1.0 <font face= symbol ></font> 10<sup>-</sup><sup>3</sup> M B)  4.0 <font face= symbol ></font><font face= symbol ></font>10<sup>-</sup><sup>12</sup> M C)  2.0 <font face= symbol ></font> 10<sup>-</sup><sup>7</sup> M D)  2.0 <font face= symbol ></font> 10<sup>-</sup><sup>3</sup> M E)  none of these Calculate the following concentrations at equilibrium:
-[Cu(CN) 2-]


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