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A 500-ML Sample of 2

question 39

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A 50.0-mL sample of 2.0 10-4 M CuNO3 is added to 50.0 mL of 4.0 M NaCN. Cu+ reacts with CN- to form the complex ion Cu(CN) 32-: A 50.0-mL sample of 2.0 <font face= symbol ></font> 10<sup>-</sup><sup>4</sup> M CuNO<sub>3</sub> is added to 50.0 mL of 4.0 M NaCN. Cu<sup>+</sup> reacts with CN<sup>-</sup> to form the complex ion Cu(CN) <sub>3</sub><sup>2</sup><sup>-</sup>:   What is the concentration of CN<sup>-</sup> at equilibrium? A)  6.0 <font face= symbol ></font> 10<sup>-</sup><sup>4</sup> M B)  1.0 M C)  4.0 M D)  2.0 M E)  none of these What is the concentration of CN- at equilibrium?


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