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When 100 Mol of a Pure Liquid Is Vaporized at a a Constant

question 6

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When 1.00 mol of a pure liquid is vaporized at a constant pressure of 1.06 atm and at its boiling point of 313.4 K, 30.00 kJ of energy (heat) is absorbed and the volume change is +25.80 L. What is H for this process? (1 L-atm = 101.3 J)

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