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The Reaction
2NOBr \rightarrow 2NO + Br2
Exhibits the Rate Law
Rate = K[NOBr]2

question 89

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The reaction
2NOBr \rightarrow 2NO + Br2
exhibits the rate law
Rate = k[NOBr]2  The reaction 2NOBr  \rightarrow  2NO + Br<sub>2</sub> exhibits the rate law Rate = k[NOBr]<sup>2</sup>   where k = 1.0 *10<sup>-</sup><sup>5</sup> M<sup>-</sup><sup>1</sup> • s<sup>-</sup><sup>1</sup> at 25° C. This reaction is run where the initial concentration of NOBr ([NOBr]<sub>0</sub>)  is 1.00 * 10<sup>-</sup><sup>1</sup> M. -What is one half-life for this experiment? A)  1.0 * 10<sup>6</sup> s B)  6.9 * 10<sup>4</sup> s C)  5.0 * 10<sup>-</sup><sup>1</sup> s D)  1.0 *10<sup>-</sup><sup>5</sup> s E)  none of these  where k = 1.0 *10-5 M-1 • s-1 at 25° C. This reaction is run where the initial concentration of NOBr ([NOBr]0) is 1.00 * 10-1 M.
-What is one half-life for this experiment?

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