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The Experimental Rate Law for the Decomposition of Nitrous Oxide

question 11

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The experimental rate law for the decomposition of nitrous oxide (N2O) to N2 and O2 is Rate = k[N2O]2. Two mechanisms are proposed:
I. N2O → N2 + O
N2O + O → N2 + O2
II. 2N2O The experimental rate law for the decomposition of nitrous oxide (N<sub>2</sub>O)  to N<sub>2</sub> and O<sub>2</sub> is Rate = k[N<sub>2</sub>O]<sup>2</sup>. Two mechanisms are proposed: I. N<sub>2</sub>O → N<sub>2</sub> + O N<sub>2</sub>O + O → N<sub>2</sub> + O<sub>2</sub><sub></sub><sub></sub> II. 2N<sub>2</sub>O  N<sub>4</sub>O<sub>2</sub><sub></sub>  N<sub>4</sub>O<sub>2</sub> → 2N<sub>2</sub> + O<sub>2</sub><sub></sub> Which of the following could be a correct mechanism? A)  Mechanism I with the second step as the rate-determining step. B)  Mechanism II with the second step as the rate-determining step. C)  Mechanism I with the first step as the rate-determining step. D)  Two of these could be correct. E)  None of these could be correct. N4O2
N4O2 → 2N2 + O2
Which of the following could be a correct mechanism?

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